Use this ZIMSEC O-Level Mathematics Paper 1 November 2023 marking scheme for checking answers, revision, and exam preparation in Zimbabwe.
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Questions: ZIMSEC O-Level Mathematics Paper 1 November 2023 Question Paper
This is the ZIMSEC O-Level Mathematics marking scheme for Paper 1 from November 2023. It shows how marks are awarded, so you can mark your own answers to the matching question paper. See the question paper.
Mathematics
November 2023 - Paper 1
Solutions provided and presented by Sir Tateada
\[
0780576282
\]
1 (a) 4,70
(b) 800
(c) $2,31 \times 10^{-3}$
2 (a) $\underline{7} \times 8^{3}+\underline{0} \times 8^{2} \times \underline{1} \times 8^{1}+\underline{6} \times 8^{0}$
\[
=7016_{8}
\]
Altematively, $7 \times 8^{3}+0 \times 8^{2}+1 \times 8^{1}+6 \times 8^{0}=3598,0$
Converting to base $8 \Rightarrow$
8 | $35^{3} 9^{7} 8$ | & |
8 | $44^{4} 9$ | $r$ | 6
8 | 5 | 6 | $r$ | 1
8 | & 7 | $r$ | 0 | & 0 | $r$ | 7
$|$
\[
=70168
\]
(b)
$\left.\begin{array}{c|rc}6 | 57 | 6 | 9 | r 6 | 1 | r 3 0 | r 1\end{array}\right\}$
(c) $\begin{array}{r}1111 +\quad 12 10002\end{array}$
(a) 2.17 am
(b)(i) 0
(ii) 2
(a)
\[
\begin{aligned}
f(x)=3 x-1 |
f(x)+f(-2) | =3(-2)-1 | =-6-1 | =-7
\end{aligned}
\]
(b)
\[
\begin{aligned}
f(x) | =5
3 x-1 | =5
3 x | =6
x | =2
\end{aligned}
\]