Use this ZIMSEC O-Level Mathematics Paper 2 November 2024 marking scheme for checking answers, revision, and exam preparation in Zimbabwe.
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Questions: ZIMSEC O-Level Mathematics Paper 2 November 2024 Question Paper
This is the ZIMSEC O-Level Mathematics marking scheme for Paper 2 from November 2024. It shows how marks are awarded, so you can mark your own answers to the matching question paper. See the question paper.
7
1
Number | Answer | Mark | Addilionsal yundance
(a)
\[
962 \times 2 \times 2 \times 2 \times 2 \times 3 \text { or } 120=2 \times 2 \times 2 \times 3 \times 5 \mathrm{M} 1
\]
24
(अ) $2 \times 2 \times 2 \times 3$ or equiv M1 ar equivalent
(b) $\_\_\_\_$ A1
(c)
$\frac{32\left({ }^{\circ} \mathrm{C}\right)}{(7 \times 4,2)}$
\[
\left.32{ }^{\circ} \mathrm{C}\right)
\]
M1
(b) $\quad \frac{32\left({ }^{\circ} \mathrm{C}\right)}{2,94 \times 10^{3} \mathrm{tz}}$
(d) $\_\_\_\_$ $2,94 \times 10^{3}$
$\_\_\_\_$
\[
3 \sqrt{7}+2 \sqrt{7}
\]
M1
A1
AWW (a) i] $b$ no penatty (c) $[j]$ or penalty
2
Number Answer | Mark Addifional guidaned NOTES
(a) $1 \times 2$ | -Bracter are
essenfic
\[
\frac{1 \times 2}{\left(\begin{array}{cc}
2 | 2
-8 | 8
\end{array}\right)}
\]
[Y] - Brackets are essen
$\left(\begin{array}{cc}30 | -20
-48 | 50\end{array}\right) \quad$ [2] $\quad$
B2
-1 each error
Praction lines - 1 once
(c)
\[
(x-1)(x+3)-2 \times 6=0
\]
\[
x^{2}-x+3 x-3-12=0
\]
[2]
(4) ii
\[
x^{2}+2 x-15=0
\]
\[
x=3 \text { or } x=-5
\]
\[
\begin{array}{l}
(x-1)(x+3)-2 \times 6=0 \mathrm{Ml}
x^{2}-x+3 x-3-12=0 \mathrm{Al}
\end{array}
\]
ANW (a) nopenalfy (b) no penalty c(i) 0 ii $i+1$
3
$(x-3)(x+5)=0$
$(x)=3$ or $(x)=-5$ Number Answer Mark. Adfitional guidame
M1
A1A1
(a)
(i) | & $\frac{100}{115}$ | ($) $2400[2]$ | $\frac{($) 24}{2760}$
\cline { 2 - 2 } (ii) | $\begin{array}{l}\text { (P) } 306,
67\end{array}$ | {$[2]$}
AI NWW
B1
(9)
(b) (i)
[2]
B2
- leach error
nce
(ii)
(2) $\quad \begin{array}{l}\text { B2 } -1 \text { each error }\end{array}$
c)
101
ANW
$a(j) 11]$
(II) [1] (III) [I]
b) (J)
M1
(iii)
\[
\text { (P) } 306,67 \quad 2 \cdot \mathrm{clp}
\]
M1
A1
($) 2 221,80
[3]
$23 \times 2760$ or $\frac{3,5}{100} \times 2760$
$23 \times 2760 \times \frac{3,5}{100}$
A1
(b)
($) 2 221,80
M1
42
($) 2
434,50
[3]
\[
50 \times 2,25+50 \times 4,51+200 \times 11,26+75 \times 12,94
\]
11,26 or $75 \times 12,94 \mathrm{MI}$
($)
\[
\begin{array}{l}
Z-434,50
3560,50
\end{array} \quad \mathrm{Al}^{\mathrm{MT}}
\]
A1
107
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