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This is the ZIMSEC O-Level Mathematics study guide for Paper 2 from November 2023. It is a free study guide for revision.
- Maths 0 Level
November 2023 Paper 2
Solution Curide and Tutorial prepared and presented by Sir Tatenda
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\[
\begin{aligned}
\text { 1(a)(i) Percentage Increase } | =\frac{\text { New Prie-o1d Prie }}{\text { ord Prie }} \times \frac{100}{1} | =\frac{1,50-1,20}{1,20} \times \frac{100}{1} | =25 \%
\end{aligned}
\]
(ii)
\[
\begin{aligned}
\frac{120}{100} x | =264
1,2 x | =2,64
x | =\frac{2,64}{1,2}
x | =220 \mathrm{~g}
\end{aligned}
\]
(iii) $\frac{7}{100} x=91$
\[
\begin{aligned}
0,07 x | =91
x | =\frac{91}{0,07}
x | =1300
\end{aligned}
\]
(b) Remembers, the angle in a semicircle is a right angle. $A \hat{C} B=90^{\circ} \triangle A B C$ is a right-angle triangle
Pythagoras $\Rightarrow a^{2}+b^{2}=c^{2}$
\[
\begin{array}{l}
A B^{2}=A C^{2}+C B^{2}
A B^{2}=7,5^{2}+5^{2}
A B^{2}=56,25+25
A B^{2}=81,25
A B=\sqrt{81,25}
A B=9,01 \mathrm{~cm}
\end{array}
\]