Download and practise with this ZIMSEC O-Level Mathematics Paper 2 June 2023 question paper. Useful for exam revision, past paper practice, and preparation in Zimbabwe.
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This is the ZIMSEC O-Level Mathematics question paper for Paper 2 from June 2023. Use it for exam practice under timed conditions. The paper code is 4004/2. Time allowed: 2 hours 30 minutes.
# ZIMBABWE SCHOOL EXAMINATIONS COUNCIL
General Certificate of Education Ordinary Level
**MATHEMATICS**
PAPER 2
4004/2
JUNE 2023 SESSION
2 hours 30 minutes
Additional materials:
Mathematical Instruments
Mathematical Tables
Non programmable Electronic Calculator
Plain Paper (1 sheet)
Graph Paper (4 sheets)
Answer Paper
Time 2 hours 30 minutes
### INSTRUCTIONS TO CANDIDATES
Write your Name, Centre number and Candidate number in the spaces provided on the answer paper/answer booklet.
Answer all questions in Section A and any four questions from Section B.
Write your answers on the separate answer paper provided.
If you use more than one sheet of paper, fasten the sheets together.
All working must be clearly shown on the same sheet as the rest of the answer.
Omission of essential working will result in loss of marks.
If the degree of accuracy is not specified in the question and if the answer is not exact, the answer should be given correct to three significant figures. Answers in degrees should be given correct to one decimal place.
Mathematical tables and Non-programmable electronic calculators may be used to evaluate explicit numerical expressions.
### INFORMATION FOR CANDIDATES
The number of marks is given in brackets [ ] at the end of each question or part question.
This question paper consists of 10 printed pages and 2 blank pages.
Copyright: Zimbabwe School Examinations Council, J2023.
**SECTION A [52 MARKS]**
Answer all questions in this section.
## Question 1
### (a)
Simplify \(0,92-0,33+0,24\), giving the answer in standard form.
### (b)
Amos sold a radio for \($ 66,00\) and made a profit of \(10 \%\).
Find the cost price of the radio.
### (c)
Share \($ 286,00\) in the ratio \(1: 1 \frac{1}{2}: 4^{\circ}\)
### (d)
Remove brackets and simplify \((d+3)(6 d-1)\).
## Question 2
### (a)
Given that \(T=g+\sqrt{n^{3}-m}\),
#### (i)
Find \(T\) when \(g=-4, n=3\) and \(m=-9\),
#### (ii)
Make \(m\) the subject of the formula.
### (b)
Find the rate of interest per year when \($ 144,00\) earns \($ 22,68\) simple interest in \(3 \frac{1}{2}\) years.
### (c)
Express \(\frac{2-x}{x^{2}-4}-\frac{1+x}{x+2}\) as a single fraction in its simplest form.
## Question 3
### (a)
Solve the following equations,
#### (i)
\(\quad \frac{3}{5}(f-1)=\frac{1}{5} f\),
#### (ii)
\(\left(2 \frac{2}{3}-p\right)^{2}=1 \frac{7}{9}\)
### (b)
Factorise completely,
#### (i)
\(\quad 10 m^{2}-t r-2 m t+5 m r\),
#### (ii)
\(\quad p^{3}-16 p\).
### (c)
A carpenter's wage depends on the number of hours she works. She is paid at a rate of \($ 3,65\) per hour.
## Question 4
Answer the whole of this question on a sheet of plain paper.
Use ruler and compasses only for your constructions.
Show all construction arcs and lines clearly.
All construction should be in a single diagram.
### (a)
Construct,
#### (i)
a quadrilateral ABCD in which \(A \hat{B} C=135^{\circ}, B \hat{A} D=60^{\circ}\),
\(B C=6,6 \mathrm{~cm}, A B=4,8 \mathrm{~cm}\) and \(A D=8,9 \mathrm{~cm}\),
#### (ii)
the locus of points equidistant from AB and BC ,
#### (iii)
the locus of points that are 3 cm from AB on the same side of AB as DC,
### (b)
Mark and label a point P , that is equidistant from AB and BC and 3 cm from AB .
### (c)
Measure and write down the length of PC.
## Question 5
### (a)
Simplify
#### (i)
\(25,8-13+15,25\)
#### (ii)
| days | hrs | mins |
| ---: | ---: | ---: |
| 3 | 15 | 40 |
| +2 | 8 | 40 |
### (b)
Tafadzwa borrows \($ 600\) from his brother Tendai at the beginning of the year. He invests the money and agrees that at the end of the year he will repay Tendai and give him 2 of any profit he will make. If the \($ 600\) increases to \($ 1250\), calculate how much he should give Tendai at the end of year.
### (c)
#### (i)
Express 676 as a product of its prime factors in index notation.
#### (ii)
Hence or otherwise find the square root of 676 .
### (d)
Given that \(f(x)=3 x+5\), find
#### (i)
\(f(3)\).
#### (ii)
the value of \(x\) for which \(f(x)=83\).
**SECTION B [48 MARKS]**
Answer any four questions from this section.
Each question carries 12 marks.
## Question 6
### (a)
The cost \(C\), of printing a newspaper is partly constant and partly varies as \(n\), the number of printed newspapers.
#### (i)
Express \(C\) in terms of \(n\) and constants \(k\) and \(h\).
#### (ii)
If the cost of printing 500 newspapers is \($ 320\) and the cost of printing 1000 newspapers is \($ 540\), find the cost of printing 750 newspapers.
### (b)
In the diagram \(K L M N\) is a trapezium in which \(K L\) is parallel to \(N M . K \hat{L} M=90^{\circ}, K L=(3 x-1) \mathrm{cm}, N M=(x+3) \mathrm{cm}\) and \(L M=(x-3) \mathrm{cm}\).
#### (i)
Find in terms of \(x\) an expression for the area of the trapezium.
#### (ii)
Given that the area of the trapezium is \(15 \mathrm{~cm}^{2}\), form an equation in \(x\) and show that it reduces to \(2 x^{2}-5 x-18=0\).
#### (iii)
Solve the equation \(2 x^{2}-5 x-18=0\).
#### (iv)
Find the length of \(L M\).
## Question 7
### (a)
The following is an extract of an incomplete water bill for a family.
The family is allowed to use 11 kilolitres (KL) of water per month at a certain rate.
If the family uses more than 11 kilolitres of water the rate increases to \($ 2,50\) per kilolitre.
| Description | Previous reading | Present reading | Consumption | Rate | Amount |
| :--- | :--- | :--- | :--- | :--- | :--- |
| | (KL) | KL | KL | $/KL | $ |
| Water | 762 | 776 | \(c\) | | |
| Permitted Consumption | | | 11 | \(r\) | 17,05 |
| Fixed Charge | | | | | 7.30 |
| Excess | | | \(s\) | 2,50 | \(t\) |
| Amount Due | | | | | \(w\) |
Calculate
#### (i)
\(c\), the consumption for the month,
#### (ii)
\(r\), the rate of permitted consumption,
#### (iii)
\(s\), the excess amount of water,
#### (iv)
\(t\), the amount …