Use this ZIMSEC O-Level Mathematics Paper 1 November 2016 marking scheme for checking answers, revision, and exam preparation in Zimbabwe.
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This is the ZIMSEC O-Level Mathematics marking scheme for Paper 1 from November 2016. It shows how marks are awarded, so you can mark your own answers.
1
(i) $\frac{1}{-2+i} \times \frac{-2-i}{-2-i}$
Rationalising or A.
\[
\begin{array}{l}
=\frac{-2}{5}-\frac{1}{5}
|u|=\sqrt{\left(\frac{-2}{5}\right)^{2}+\left(\frac{-1}{5}\right)^{2}}
=\frac{\sqrt{5}}{5} \text { or equiv. }
\end{array}
\]
\[
\text { (ii) } \begin{aligned} | \left.\left.\arg (u)=(\bar{u})+\tan ^{\frac{1}{5}} / \frac{2}{5}\right)\right] | =\quad-2.68^{\circ} \text { or }-153.4^{\circ}
\end{aligned}
\]
$2(9+2 x)^{\frac{-3}{2}}=9^{\frac{-4}{2}}\left(1+\frac{2 x}{9}\right)^{\frac{-4}{2}}$
Expressing in exp
\[
\begin{array}{l}
=\quad \frac{1}{27}\left[1+\left(\frac{-3}{2}\right)\left(\frac{2 x}{9}\right)+\frac{\left(\frac{-3}{2}\right)\left(\frac{-5}{2}\right)\left(\frac{2 x}{9}\right)^{2}}{2!} \ldots\right]
=\quad \frac{1}{27}-\frac{x}{81}+\frac{5}{1458} x^{2}
\end{array}
\]
$3 x x^{2}+(2 m x+c)^{2}=4$
Attempt solving simultar
\[
\begin{array}{l}
\left(1+4 m^{2}\right) x^{2}+4 m c x+c^{2}-4=0
(4 m c)^{2}-4\left(1+4 m^{2}\right)\left(c^{2}-4\right)=0
\end{array}
\]
Use of discriminant
Correct reduction to
\[
10 m^{2}-c^{2}+4=0
\]
A.G