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ZIMSEC O-Level Mathematics Paper 2 June 2016 Question Paper

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Exam board
ZIMSEC
Subject
Mathematics
Level
O-Level
Document
Question Paper
Paper
Paper 2
Paper code
4030/2
Time allowed
2 hours 30 minutes
Session
June
Year
2016
File
PDF, 1.5 MB

About this question paper

This is the ZIMSEC O-Level Mathematics question paper for Paper 2 from June 2016. Use it for exam practice under timed conditions. The paper code is 4030/2. Time allowed: 2 hours 30 minutes.

More Mathematics O-Level 2016 papers

Other years: Mathematics O-Level

Extracted text

# ZIMBABWE SCHOOL EXAMINATIONS COUNCIL <br> General Certificate of Education Ordinary Level

**MATHEMATICS <br> PAPER 2**

JUNE 2016 SESSION
2 hours 30 minutes
Candidates answer on the question paper.
Additional materials: Geometrical instruments
Mathematical tables/ Electronic calculator
Allow candidates 5 minutes to count pages before the examination.

This booklet should not be punched or stapled and pages should not be removed.
TIME 2 hours 30 minutes

### INSTRUCTIONS TO CANDIDATES

Write your name, Centre number and candidate number in the spaces at the top of this page and your Centre number and Candidate number on the top right corner of every page of this paper.

Answer all questions in Section A and any three from Section B.
Check that all the pages are in the booklet and ask the invigilator for a replacement if there are duplicate or missing pages.
Write your answers in the spaces provided on the question paper using black or blue pens.
If working is needed for any question, it must be shown in the space below that question.
Omission of essential working will result in loss of marks.
Decimal answers which are not exact should be given correct to three significant figures unless stated otherwise. Answers in degrees should be given to one decimal place.

### INFORMATION FOR CANDIDATES

The number of marks is given in brackets [ ] at the end of each question or part question.
Mathematical tables or Electronic calculators may be used to evaluate explicit numerical expressions.

**This question paper consists of 26 printed pages.**

Copyright: Zimbabwe School Examinations Council, J2016.

| Centre Number | Candidate Number |
| :--- | :--- |
|  |  |

## 2

**Section A [64 marks]**
Answer all the questions in this section.

## Question 1
### (a)

Simplify \(7 \frac{1}{2}+\frac{1}{2} \times 8-2\).

Answer
(a)

### (b)

Find the Lowest Common Multiple (L.C.M) of 60 and 84.

| Centre Number | Candidate Number |
| :--- | :--- |
|  |  |

## 3

### (c)

Mary, Peter and John share a total amount of \($ 500\) in the ratio 3:2:5. Mary uses part of her share to buy a pair of shoes costing \($ 30\).

#### (i)

Calculate Mary's share.

Answer
(c)
(i)
§
[2]

#### (ii)

Calculate the percentage of Mary's share that is left.

| Centre Number | Candidate Number |
| :--- | :--- |
|  |  |

## 4

## Question 2
### (a)

Factorise completely

#### (i)

\(4 c^{2}+12 c n\),

Answer
(a)
(i)
[1]

#### (ii)

Factorise completely \(k^{2}+k h-k p-h p\).

Answer
(ii)
[2]

### (b)

Solve the equation
\(\frac{12-y}{3}=5-2 y\).

Answer
(b) \(y=\)
[2]

| Centre Number | Candidate Number |
| :--- | :--- |
|  |  |

## 5

### (c)

The mass, \(m\) grams, of a solid, is inversely proportional to its volume, \(v \mathrm{~cm}^{3}\).

#### (i)

Find the formula connecting \(m\) and \(v\), given that \(m=3,5 \mathrm{~g}\) when \(v=4 \mathrm{~cm}^{3}\).

Answer (c) (i) [2]

#### (ii)

Find \(m\) when \(v=6 \mathrm{~cm}^{3}\).

Answer
(ii) \(m=\)
[1]

### (d)

Make \(x\) the subject of the formula \(w x^{2}=n\).

Answer
(d) \(x=\)
[2]

![](https://ocr.unopasa.com/p/ocr_assets/e4868d74171da41eb694004c7fe14293840f42bba87225eecb502d9d3eb7731b.jpg)

## 6

## Question 3
### (a)

In the diagram, \(L \hat{M} N=90^{\circ}, M N=x c m, M L=(x+3) \mathrm{cm}\) and \(L N=7 \mathrm{~cm}\).

#### (i)

Form an equation in \(x\) and show that it reduces to \(x^{2}+3 x-20=0\).

Answer (a) (i)

#### (ii)

Solve the equation \(x^{2}+3 x-20=0\), giving the answers correct to 2 significant figures.

Answer
(ii) \(x=\) \(\_\_\_\_\) or \(\_\_\_\_\) [4]

| Centre Number | Candidate Number |
| :--- | :--- |
|  |  |

## 7

#### (iii)

Hence calculate the perimeter of the triangle LMN.

Answer
(iii)

cm [2]

### (b)

A form four class has 40 pupils. All of them were asked whether they would like to study Mathematics or Physics after form four. Some of the results are shown in the Venn diagram.

![](https://ocr.unopasa.com/p/ocr_assets/3f5fef423f6db0ccc592be3eeebad36f70f2065d2adab13715e0d5f3c58c54c1.jpg)

The Universal set, \(\boldsymbol{\xi}\) is the set of all pupils in the class. M is the set of pupils who like Mathematics. P is the set of pupils who like Physics.

#### (i)

Find \(\mathrm{n}(M \cup P)\),

Answer
(b) (i)
[1]

#### (ii)

Find the number of pupils who do not like either subject,

Answer
(ii)
[1]

![](https://ocr.unopasa.com/p/ocr_assets/7a0d849d6e4bb7f3dceb950ead8f7ab524436b78db5c26af5123ac13a4f8de60.jpg)

## 8

#### (iii)

Find \(\mathrm{n}\left(M^{l} \cap P\right)\).

Answer (iii)
\(\_\_\_\_\)

## Question 4
![](https://ocr.unopasa.com/p/ocr_assets/940f7b46b9599adf639ac1796db44339e67679a107fc82021371368ec1df4327.jpg)

In the diagram, J, K, M and L lie on the circumference of a circle. JM and KL intersect at \(\mathrm{H} . \mathrm{JHK}=97^{\circ}, \mathrm{J} \hat{\mathrm{KH}}=48^{\circ}, \mathrm{KH}=20 \mathrm{~cm}, \mathrm{JH}=25 \mathrm{~cm}\) and \(\mathrm{HM}=6 \mathrm{~cm}\).

### (a)

Find HL̂M.

Answer
(a) \(\mathrm{H} \hat{\mathrm{L} M}=\) \(\_\_\_\_\) [3]

| Centre Number | Candidate Number |
| :--- | :--- |
|  |  |

## 9

### (b)

Name, in the correct order, the triangle which is similar to triangle JKH.

Answer
(b)
[1]

### (c)

Calculate

#### (i)

the length of JK,

Answer
(c)
(i) \(\mathrm{JK}=\) \(\_\_\_\_\) cm [3]

#### (ii)

the area of the triangle JKH ,

Answer
(ii) \(\_\_\_\_\) \(\mathrm{cm}^{2}\) [2]

| Centre Number | Candidate Number |
| :--- | :--- |
|  |  |

## 10

#### (iii)

the area of triangle HLM.

Answer
(iii) \(\_\_\_\_\) \(\mathrm{cm}^{2}\) [3]

## Question 5
### (a)

Given that
\(\mathbf{A}=\left(\begin{array}{cc}2  |  5  -3  |  y\end{array}\right), \mathbf{B}=\left(\begin{array}{ll}-4  |  3\end{array}\right)\) and \(\mathbf{C}=\left(\begin{array}{cc}5  |  -4  2  |  -9\end{array}\right)\),

#### (i)

find the value of \(y\) for which \(\mathbf{A}\) has no inverse,

Answer
(a) (i) \(y=\) \(\_\_\_\_\) [2]

#### (ii)

evaluate \(\mathbf{A}+\mathbf{C}\), using the value of y in (i).

Answer
(a)
(ii) …