Use this ZIMSEC O-Level Mathematics Paper 1 June 2018 marking scheme for checking answers, revision, and exam preparation in Zimbabwe.
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Questions: ZIMSEC O-Level Mathematics Paper 1 June 2018 Question Paper
This is the ZIMSEC O-Level Mathematics marking scheme for Paper 1 from June 2018. It shows how marks are awarded, so you can mark your own answers to the matching question paper. See the question paper.
Zimsec Ordinary Level Mathematics
June 2018 Paper 1 Suggested Answers
1. a) i) $3.598 \times 10^{3}$
ii) 3600
b) 60
2. a) i) 4.885
ii) 0.4752
b) $4 \frac{5}{24}$
3. a) 12.25 am
b) i) Friday
ii) 0015
4. a) 0.3
b) $\frac{4}{3}$
c) $\frac{1}{9}$
5. a) 9
b) 24
6. a) 647
b) $35_{6}$
7. a) $42^{\circ}$
b) $48^{\circ}$
c) $96^{\circ}$
8. a) 24
b) $2^{2(2 n-3)}=2^{3}$ gives $\mathrm{n}=\frac{9}{4}$
9. a) Diagram
9. $(P \cap Q) \cup(P \cap R)$ or equivalent.
10. a) $y=k(x=3)^{2}$
b) $k=4, y=196$
11. $x=4 \frac{1}{2} \quad \mathrm{y}=1$
12. a) $-\frac{3}{2}$
b) ( 0 ; 6)
13. $\frac{3 x^{2}}{x(x-5)} \times \frac{(x-5)(x+5)}{x}=3(x-5)$
14. a) 86
b) $\frac{5(F-32)}{9}$
15. a) $-23 x+21$ or $31-23 x$
b) $3.35 \times 6=20.1 \mathrm{~cm}$
16. a) i) $x(x+1)(x-1)$
ii) $(x+1)^{2}$
b) $(x+1)$
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17. a) $\binom{5}{-4-x}$
b) i) 5
ii) $\binom{6}{-8}=\binom{6}{-3 x} \quad x=\frac{8}{3}$
18. a) 13
b) $\frac{x+76}{7}=13 \quad x=15$
19. a) $\frac{1}{2}$
b) Question is not clear. 1 is both a perfect square and a factor of 21. Refer to similar questions.
20. a) i) $x<\frac{13}{2}$
ii) 4
b) Scale factor $=\frac{3}{2} \quad$ Volume factor $=\frac{27}{8}$
\[
\text { Mass }=\frac{27}{8} \times 40=135 g
\]
21. a) $15.66 \mathrm{~cm}^{2}$
b) $\sqrt{133} \mathrm{~cm}$
22. a) $\frac{18}{4}=4.5 \mathrm{~m} / \mathrm{s}^{2}$
b) Area under the graph $=234 \mathrm{~m}$.
c) $\frac{30}{T-9}=6$ (Deceleration) so $T=14 s$
23. a) 10 cm
b) Add areas of 5 faces: $624 \mathrm{~cm}^{2}$
24. a) i) $\log _{3} 9=2$
ii) -1
b) $\log 23+\log 81^{\frac{1}{2}}=\log (8 \times 9)=\log 72$.
25. i) $p=5$
ii) $q=-7$
ii) $r=9$
26. a) Translation of vector $\binom{3}{-6}$
b) i) $y=-x$
ii) $\left(\begin{array}{cc}0 | -1 -1 | 0\end{array}\right)$