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Lockdown Pure Maths Test 17

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Questions: Trockers A-Level Pure Mathematicsugust 2020 Question Paper

Subject
Pure Mathematics
Level
A-Level
Document
Marking Scheme
Session
August
Year
2020
File
PDF, 666 KB

About this marking scheme

This is the A-Level Pure Mathematics marking scheme from August 2020. It shows how marks are awarded, so you can mark your own answers to the matching question paper. See the question paper.

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Other years: Pure Mathematics A-Level

Text from the first page

Upper $6{ }^{\text {th }}$
LOCKDOWN PURE MATHS TEST 17
Sunday 09 August 2020
ANSWERS

30 MARKS

NB: If a numerical answer cannot be given exactly, and the accuracy required is not specified in the question, then in the case of an angle it should be given to the nearest degree, and in other cases it should be given correct to $\mathbf{2}$ significant figures.
1. By means of substitution $2 u=\cos x$, show that
\[
\int_{0}^{\frac{1}{2}} 4 u^{2} \sqrt{\left(1-4 u^{2}\right)} d u=\frac{1}{8} \int_{0}^{\frac{\pi}{2}} \sin ^{2} 2 x d x
\]
and hence find the exact value of $\int_{0}^{\frac{1}{2}} 4 u^{2} \sqrt{\left(1-4 u^{2}\right)} d u$.

[4]
\[
\int_{0}^{\frac{1}{2}} 4 u^{2} \sqrt{\left(1-4 u^{2}\right)} d u
\]

Let $2 u=\cos x$
\[
\begin{array}{l}
\Rightarrow 2 \frac{d u}{d x}=-\sin x
\Rightarrow d u=-\frac{\sin x}{2} d x
\end{array}
\]

Changing of limits:

\multicolumn{3}{c}{$x=\cos ^{-1}(2 u)$}
 $\boldsymbol{u}$  |  $\mathbf{0}$  |  $\frac{\mathbf{1}}{\mathbf{2}}$
 $\boldsymbol{x}$  |  $\frac{\pi}{2}$  |  0

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