Use this ZIMSEC A-Level Pure Mathematics Paper 1 November 2020 marking scheme for checking answers, revision, and exam preparation in Zimbabwe.
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Questions: ZIMSEC A-Level Pure Mathematics Paper 1 November 2020 Question Paper
This is the ZIMSEC A-Level Pure Mathematics marking scheme for Paper 1 from November 2020. It shows how marks are awarded, so you can mark your own answers to the matching question paper. See the question paper.
PURE MATHS 1 Marking Scheme 2020.
Q1
\[
\begin{aligned}
3 x-4 y | +2=0
y | =\frac{3}{4} x+\frac{1}{2} .
\Rightarrow \quad | m_{1}=\frac{3}{4}
\end{aligned}
\]
If the line passing through $(2 ;-3)$ is parallel to $3 x-4 y+2=0$
\[
\begin{array}{l}
\Rightarrow \text { its gradient }=\frac{3}{4}
\therefore \quad \begin{aligned}
y-y_{1} | =m\left(x-x_{1}\right)
y--3 | =\frac{3}{4}(x-2)
y+3 | =\frac{3}{4} x-\frac{3}{2}
y | =\frac{3}{4} x-\frac{3}{2}-3
4 y | =3 x-6-12 .
3 x | -4 y-18=0
\end{aligned}
\end{array}
\]
Qu 2
\[
\begin{aligned}
2^{3 x-2} | =6
\Rightarrow \ln 2^{3 x-2} | =\ln 6
(3 x-2) \ln 2 | =\ln 6
3 x-2 | =\frac{\ln 6}{\ln 2}
3 x | =2+\frac{\ln 6}{\ln 2}
\end{aligned}
\]
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