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First page of ZIMSEC A-Level Pure Mathematics Paper 1 November 2021 Marking Scheme

ZIMSEC A-Level Pure Mathematics Paper 1 November 2021 Marking Scheme

Use this ZIMSEC A-Level Pure Mathematics Paper 1 November 2021 marking scheme for checking answers, revision, and exam preparation in Zimbabwe.

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Questions: ZIMSEC A-Level Pure Mathematics Paper 1 November 2021 Question Paper

Exam board
ZIMSEC
Subject
Pure Mathematics
Level
A-Level
Document
Marking Scheme
Paper
Paper 1
Session
November
Year
2021
File
PDF, 556 KB

About this marking scheme

This is the ZIMSEC A-Level Pure Mathematics marking scheme for Paper 1 from November 2021. It shows how marks are awarded, so you can mark your own answers to the matching question paper. See the question paper.

More Pure Mathematics A-Level 2021 papers

Other years: Pure Mathematics A-Level

Text from the first page

CHAKS SOLUTIONS
November 2021 Pure Mathematics P1
Suggested marking guide
6042
BY CHAKUAMBA FORTUNE T (CHAKS)
+263771580933
1) $2 e^{2 x}-7 e^{x}+6=0$
$2\left(e^{x}\right)^{2}-7 e^{x}+6=0$
Let $a$ be $e^{x}$
$\Rightarrow 2 a^{2}-7 a+6=0$
$2 a^{2}-3 a-4 a+6=0$
$a(2 a-3)-2(2 a-3)=0$
$(a-2)(2 a-3)=0$
$a=2$ or $\frac{3}{2}$
But $a=e^{x}$
$\Rightarrow e^{x}=2$
OR
\[
e^{x}=\frac{3}{2}
\]

Applying natural logarithms
\[
\begin{array}{l}
\operatorname{In} e^{x}=\operatorname{In} 2
x=\operatorname{In} 2
\text { OR }
\operatorname{In} e^{x}=\operatorname{In} \frac{3}{2}
x=\operatorname{In} \frac{3}{2}
\end{array}
\]

PAGE 1CHAKS SOLUTIONS +263771580933 chakuambafortunet@gmail.com