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First page of ZIMSEC O-Level Mathematics Paper 1 November 2009 Marking Scheme

ZIMSEC O-Level Mathematics Paper 1 November 2009 Marking Scheme

Use this ZIMSEC O-Level Mathematics Paper 1 November 2009 marking scheme for checking answers, revision, and exam preparation in Zimbabwe.

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Questions: ZIMSEC O-Level Mathematics Paper 1 November 2009 Question Paper

Exam board
ZIMSEC
Subject
Mathematics
Level
O-Level
Document
Marking Scheme
Paper
Paper 1
Session
November
Year
2009
File
PDF, 1.5 MB

About this marking scheme

This is the ZIMSEC O-Level Mathematics marking scheme for Paper 1 from November 2009. It shows how marks are awarded, so you can mark your own answers to the matching question paper. See the question paper.

More Mathematics O-Level 2009 papers

Other years: Mathematics O-Level

Text from the first page

Cmeral term
\[
\begin{array}{l}
\binom{9}{r}\left(x^{2}\right)^{9-r}\left(\frac{-2}{x}\right)
\frac{x^{2(9-r)}}{x^{r}}=\frac{1}{x^{3}}
18-2 r-r=-3
r=7,
=\binom{9}{7}\left(x^{2}\right)^{2}\left(\frac{-2}{x}\right)^{7}
=-4608 \frac{1}{x^{3}}
\end{array}
\]

Correct method of identifying term
N
,

Correctly identified term

Al

Use of binomial formular

M1

Term

Coefficient
\[
=-4608
\]
$\cos 60^{0}=\frac{c^{2}+3^{2}-7^{2}}{2(3) c}$
\[
\begin{array}{l}
1
2
2 c^{2}-6 c-80=0
(c-8)(c-)=0
\begin{array}{c}
c=8 \quad \quad c=-5
\therefore c=8
\end{array}
\operatorname{Cos} C=\frac{7^{2}+3^{2}-8^{2}}{2(3) 7}
\quad=\frac{-6}{42}
\quad=-\frac{1}{7}
\frac{A}{(x+2)^{2}}+\frac{B}{(x+2)}+\frac{C}{(3-x)}
5 x^{2}+7 x+9=A(3-x)+B(x+2)(3-x)+C(x+2)^{2}
x=3 \Rightarrow 75=25 c \Rightarrow c=3
x=0,15=5 A \Rightarrow A=3
x=0,9=9+6 B+12 \Rightarrow B=-2
\end{array}
\]
for method of finding Cons ?
for validly obtaining given answer
correct structure
correct method of obtaining coefficient
eacn corred coemoled
coefficient
c.a.o
for correct quadratic in c
A1

[4]

for method of finding $c$

M!
A1

M1
M1
NOS/M/S16401