Use this ZIMSEC A-Level Physics Paper 2 November 2011 marking scheme for checking answers, revision, and exam preparation in Zimbabwe.
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Questions: ZIMSEC A-Level Physics Paper 2 November 2011 Question Paper
This is the ZIMSEC A-Level Physics marking scheme for Paper 2 from November 2011. It shows how marks are awarded, so you can mark your own answers to the matching question paper. See the question paper.
Nov. $202119188 / 2$
(a) (i) T base units $=\mathrm{s}$
\[
\begin{array}{ll}
\sqrt{\frac{l}{g}} \text { base units }= | \left(\frac{m}{m s^{-2}}\right)^{\frac{1}{2}}
\left(\frac{m}{m s^{-2}}\right)^{\frac{1}{2}}=\left(s^{2}\right)^{\frac{1}{2}}=s | \text { seserceres } \quad \sqrt{\frac{l}{G}}=\left(\frac{m}{m}\right)^{2}
\end{array}
\]
A1
(ii) $\quad \mathrm{F}$ base units $=\mathrm{kgms}^{-2}$
\[
k g m s^{-2} \neq k g m^{3} s^{-2}
\]
✓ Not homogenous
A1
(b)
\[
\begin{array}{l}
\mathrm{kgms}^{-2}=\text { units of } \mathrm{k}\left(\mathrm{kgm}^{-3} \mathrm{~m}^{2} \mathrm{~m}^{2} \mathrm{~s}^{-2}\right)
=\text { units of } k\left(\mathrm{kgms}^{-2}\right) \quad k=\frac{q}{p r^{2} v^{2}}
\text { units of } \mathrm{k}=\frac{\mathrm{kgms}^{-2}}{\mathrm{kgms}^{-2}}=1
\text { uncts of } k=\frac{12 y m 5^{2}}{12 y m^{-3} m^{2} m^{2} 5^{2}}
\text { M1 }
\mathrm{k} \text { has no units }
\text { reject } k=\frac{k g m s^{2}}{k g m^{3} m^{2} m^{2} s^{2}}
\text { (i) } \quad \omega=\frac{2 \pi}{T} / 2 \pi f=W
\end{array}
\]
A1
2
\[
\begin{array}{l}
=\frac{2 \pi}{\frac{1}{2}}
=4 \pi=12.6 \mathrm{rad} \mathrm{~s}^{-1}
\end{array}
\]
A1
(ii)
\[
\begin{aligned}
v=\omega r | =12.6 \times\left(\frac{2.1}{4.50+0.60}\right) \cos 30 r=2,1 \cos 30 \cdots \mathrm{ci} | =22.85 \mathrm{~ms}^{-1} / 22,92 \mathrm{~ms} / 23,6+\mathrm{m} / \mathrm{s}
\end{aligned} \mathrm{Clc}
\]
C1C1
C1
A1
(iii) Vertical motion
\[
\begin{array}{c}
v^{2}=u^{2}+2 g s \Rightarrow v^{2}=0+2 \times 9.81 \times 2.0
=\quad 39.24 \mathrm{~m}
\end{array}
\]