Use this ZIMSEC A-Level Mathematics Paper 1 November 2008 marking scheme for checking answers, revision, and exam preparation in Zimbabwe.
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Questions: ZIMSEC A-Level Mathematics Paper 1 November 2008 Question Paper
This is the ZIMSEC A-Level Mathematics marking scheme for Paper 1 from November 2008. It shows how marks are awarded, so you can mark your own answers to the matching question paper. See the question paper.
$\sim 2008 \quad 91841$
$1 \quad\left|z^{2}\right|=8^{2}=64$
\[
\begin{array}{l}
\arg \left(z^{2}\right)=2 \times \frac{3 \pi}{4}=\frac{3 \pi}{2}
m=-\frac{\pi}{2} \text { (p.v.) }
\end{array}
\]
B1
B1
\[
z^{2}=0-64 i
\]
correct answer (condone omission of 0 )
B1
[4]
2 (i) $y=2$ Equation of perpendicular bisector
B1
$y=2$ and $2 x+y=4$, solving simultaneously
M1
$x=1$, substitutes in given equation correctly
(ii) $\quad r=\sqrt{(1+1)^{2}+(-2 \times 1)^{2}}$ or equiv. correct method
$r=2 \sqrt{2}(\sqrt{8})$ obtain correct answer
A1
M1
A1