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Secondary Mathematics Matrices Worksheet Zimbabwe

Study Mathematics worksheet on Matrices for Secondary. Useful for revision, homework, and exam preparation in Zimbabwe.

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Subject
Mathematics
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Worksheet
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PDF, 671 KB

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Finding the values of the unknomer
- The corresponding numbers or lettes have the fame value.
\[
\begin{array}{l}
\text { e.g }\left[\begin{array}{l}
x
y
\end{array}\right]=\left[\begin{array}{l}
2
3
\end{array}\right]
\therefore \underset{\left[\begin{array}{ll}
a  |  b
c  |  d
\end{array}\right]=\left[\begin{array}{ll}
1  |  2
3  |  4
\end{array}\right]}{ }
\end{array}
\]

In this case $a=1, b=2, c=3, d=4$
Example
If $\left[\begin{array}{cc}2  |  3  1  |  x\end{array}\right]=\left[\begin{array}{cc}y  |  3  1  |  4\end{array}\right]$, find the
value of $x$ and the value of $y$ solution
Check the position of $x$ in the first matrix and its corresponding pesitum in the second matrix.
$x=4, y=2$
Try
If $\left[\begin{array}{ccc}6  |  -3  |  1  0  |  m  |  n  4  |  -1  |  -2\end{array}\right]=\left[\begin{array}{ccc}6  |  -3  |  p  2  |  -8  |  7  4  |  -1  |  -2\end{array}\right]$
Find $m, n, p$ and $q$.
Example 2
Some Matrices need to be operated first unitch the left side and the right side have one matrix each.

Find $x$ if $\left[\begin{array}{l}x  2\end{array}\right]+\left[\begin{array}{l}3  4\end{array}\right]=\left[\begin{array}{l}5  6\end{array}\right]$
\[
\left[\begin{array}{l}
x
2
\end{array}\right]+\left[\begin{array}{l}
3
4
\end{array}\right]=\left[\begin{array}{l}
5
6
\end{array}\right]
\]
\[
\begin{array}{l}
{\left[\begin{array}{c}
x+3
6
\end{array}\right]=\left[\begin{array}{l}
5
6
\end{array}\right]}
\therefore x+3=5
x=5-3
\text { 2) If } x=2
{\left[\begin{array}{cc}
1  |  -3
2  |  -4
\end{array}\right]-\left[\begin{array}{cc}
e  |  0
5  |  -10
\end{array}\right]=\left[\begin{array}{cc}
-1  |  -3
-3  |  2 f
\end{array}\right]}
\end{array}
\]

Find the value of $e$ and the value of $f$ (3)
Solution:
The left hand side should remoun with a single matrix.
\[
\begin{array}{l}
{\left[\begin{array}{cc}
1-e  |  -3+0
2-5  |  -4-(-10)
\end{array}\right]=\left[\begin{array}{cc}
-1  |  -3
-3  |  2 f
\end{array}\right]}
{\left[\begin{array}{cc}
1-e  |  -3
-3  |  6
\end{array}\right]=\left[\begin{array}{cc}
-1  |  -3
-3  |  2 f
\end{array}\right]}
\end{array}
\]

Now equate the arresponding values
\[
\begin{array}{ll}
1-e=-1  |  6=2 f
-e=-i-1  |  \frac{e}{2}=\frac{1 f}{2}
-e=-2  |  f=3
\frac{-e}{-1}=\frac{-2}{-1}  |  f=3
e=2  |
\therefore e=2, f=3  |  \end{array}
\]

Actwity 2.
Find the value of $x$ and $y$ "
\[
\text { 1) }\left[\begin{array}{cc}
-1  |  -1
0  |  6
\end{array}\right]-\left[\begin{array}{cc}
x  |  8
-2  |  4 …